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The value of RT for 5.6 L of ideal gas at S.T.P. is reported to be x times the value of PV. The value of x is
  • 2
  • 1
  • 0.25
  • 4

Abhishek Dogra , 7 Years ago
Grade 11
anser 1 Answers
Arun
Dear student
 
22.4pv=1 nRT 
5.6Pv=? nRT
solve this the answer is 4 RT
 
Regards
Arun (askIITians forum expert)
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Last Activity: 7 Years ago
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