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Same spring is attached with 2 kg, 3 kg and 1 kg blocks in three different cases as shown in figure. If x1, x2 and x3 be the respective extensions in the spring in these three cases, then :-

Shivani Matcha , 6 Years ago
Grade 12th pass
anser 1 Answers
Eshan

Last Activity: 6 Years ago

In the first case, the two blocks will stay in equilibrium because of presence of equal weight on both sides. Hence tension in the springmg=kx_1

\implies x_1=\dfrac{2g}{k}

In the second case, we first write the equation of the motion of the blocks.

3g-T=3a
andT-2g=2a
\implies T=kx_2=\dfrac{12g}{5} \implies x_2=\dfrac{12g}{5k}

In the third case,

2g-T=2a
andT-g=a
\implies x_3=\dfrac{4g}{3k}

Hencex_2>x_1>x_3

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