Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Projectile motion problem...urgent...please help fast

Projectile motion problem...urgent...please help fast

Question Image
Grade:11

1 Answers

Arun
25763 Points
one year ago
Let the initial velocity of the projectile be  and its initial angle of projection 
Since there is no acceletaion in the horizontal direction
Therefore, the horizontal velocity will be constant
The horizontal component of the velocity
The vertical componenet
The projectile covers 120 m distance with the velocity  in time  seconds
Therefore,
 ............. (1)
The vertical height obtained by projectile is given by
or, 
Since this is a quadratic equation in t therefore for any particular height there will be two values of t
we know that for the given height in the question the values of t are 2 seconds and 6 seconds
Hence from the quadratic equation
Sum of roots = -(coefficient of t)/(coefficient of t^2)
or, 
 ................(2)
Dividing eq (2) with eq (1) we get
 
 

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free