pH of an aqueous solution of 25ºC is 12. On increasing its dilution, at 25ºC, upto 10 times its new pH would be :- (1) 13 (2) 120 (3) 10 (4) 11

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Sandeep Bhamoo · Answer

Ph=14-Poh and Poh = -log(concentration of OH ion) here the concentration is decreased by a factor of 10 hence new Poh` = Poh +1 =2+1=3 hence new Ph=11 please do approve my answer if correct

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pH of an aqueous solution of 25ºC is 12. On increasing its dilution, at 25ºC, upto 10 times its new pH would be :- (1) 13 (2) 120 (3) 10 (4) 11

pH of an aqueous solution of 25ºC is 12. On increasing its dilution, at 25ºC, upto 10 times its new pH would be :-

(1) 13 (2) 120 (3) 10 (4) 11

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pH of an aqueous solution of 25ºC is 12. On increasing its dilution, at 25ºC, upto 10 times its new pH would be :- (1) 13 (2) 120 (3) 10 (4) 11

pH of an aqueous solution of 25ºC is 12. On increasing its dilution, at 25ºC, upto 10 times its new pH would be :- (1) 13 (2) 120 (3) 10 (4) 11

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pH of an aqueous solution of 25ºC is 12. On increasing its dilution, at 25ºC, upto 10 times its new pH would be :-

(1) 13 (2) 120 (3) 10 (4) 11