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In a neon discharge tube, 2.9 x 1018 Ne+ ions move to the right per second, while 1.2 x 1018 electrons move to the left per second. The current in the discharge tube is?

Fatima , 6 Years ago
Grade 12th pass
anser 2 Answers
Arun

Last Activity: 6 Years ago

Dear Fatima
 
Net current i = (2.9 * 10^18 + 1.2 * 10^18)* e = 4.1 * 10^18 * 1.6 * 10^-19
 
 =  0.656 amp towards right

Rishi Sharma

Last Activity: 4 Years ago

Dear Student,
Please find below the solution to your problem.

Net current i = (2.9 * 10^18 + 1.2 * 10^18)* e = 4.1 * 10^18 * 1.6 * 10^-19
= 0.656 amp towards right

Thanks and Regards

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