In a neon discharge tube, 2.9 x 10 18 Ne + ions move to the right per second, while 1.2 x 10 1 8 electrons move to the left per second. The current in the discharge tube is?

Question

Arun · Answer

Dear Fatima Net current i = (2.9 * 10^18 + 1.2 * 10^18)* e = 4.1 * 10^18 * 1.6 * 10^-19 = 0.656 amp towards right

Rishi Sharma · Answer

Dear Student, Please find below the solution to your problem. Net current i = (2.9 * 10^18 + 1.2 * 10^18)* e = 4.1 * 10^18 * 1.6 * 10^-19 = 0.656 amp towards right Thanks and Regards

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In a neon discharge tube, 2.9 x 10 18 Ne + ions move to the right per second, while 1.2 x 10 1 8 electrons move to the left per second. The current in the discharge tube is?

In a neon discharge tube, 2.9 x 10¹⁸ Ne⁺ ions move to the right per second, while 1.2 x 10¹⁸ electrons move to the left per second. The current in the discharge tube is?

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In a neon discharge tube, 2.9 x 10 18 Ne + ions move to the right per second, while 1.2 x 10 1 8 electrons move to the left per second. The current in the discharge tube is?

In a neon discharge tube, 2.9 x 1018 Ne+ ions move to the right per second, while 1.2 x 1018 electrons move to the left per second. The current in the discharge tube is?

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In a neon discharge tube, 2.9 x 10¹⁸ Ne⁺ ions move to the right per second, while 1.2 x 10¹⁸ electrons move to the left per second. The current in the discharge tube is?