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Grade: 11

                        

How much heat is required to raise the temperature of 85 grams of water from 280 K to 342 K? 5270 J 355 J 355 J 151 J 22029 J

one year ago

Answers : (3)

Shivangi Khatter
askIITians Faculty
468 Points
							dear student
the correct answer is(A)
Heat= mc deltaT = 85 1 62= 5270 J
one year ago
Arun
24739 Points
							
Dear student
 
as 
Q = ms (delta T) =85 *10^-3 * 4.18*10^3 * 62 = 22029 J
 
Hope it helps
 
Regards
Arun
one year ago
APARNA SHAJI
32 Points
							
THE COORECT ANSWER IS A AS 
HEAT= MC DELTA T AND C FOR WATER IS 1.
SO 85*1*62=5270 J
PLS APPROVE IF IT HELPED U
one year ago
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