MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11
        
How much heat is required to raise the temperature of 85 grams of water from 280 K to 342 K?
  1. 5270 J
  2. 355 J
  3. 355 J
  4. 151 J
  5. 22029 J
one year ago

Answers : (3)

Shivangi Khatter
askIITians Faculty
468 Points
							dear student
the correct answer is(A)
Heat= mc deltaT = 85 1 62= 5270 J
one year ago
Arun
23520 Points
							
Dear student
 
as 
Q = ms (delta T) =85 *10^-3 * 4.18*10^3 * 62 = 22029 J
 
Hope it helps
 
Regards
Arun
one year ago
APARNA SHAJI
32 Points
							
THE COORECT ANSWER IS A AS 
HEAT= MC DELTA T AND C FOR WATER IS 1.
SO 85*1*62=5270 J
PLS APPROVE IF IT HELPED U
9 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 728 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details