Guest

For the circuit shown below, when the switch S is closed, then the total amount of charge that flows from point a to point b through the switch: is

For the circuit shown below, when the switch S is closed, then the total amount of charge that flows from point a to point b through the switch: is

Question Image
Grade:12

1 Answers

Arun
25758 Points
2 years ago
When steady state is reached, the current I from the battery is 
9=I(3+6)orI=IA 
Potential difference across 3Ω resistance is 3 V and potential difference across
6Omega resistance is 6 V. 
Potential difference across 
3muF capacitor is 3V and pd 
across 6muF capacitor is 6 V. 
Therefore, charge on 3muF 
capacitor is 
Q_1 = 3 xx 3 = 9muC 

Charge on 6muF capacitor is 
Q_2 = 6 xx 6 = 36 muC 
Charge (-Q_1) is shifted from the positive plate of 6muF capacitor. 
The remaining charge on the positive plate of 6muF capacitor is 
shifted through the switch. Therefore, charge passing through 
the switch is

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free