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For the circuit shown below, when the switch S is closed, then the total amount of charge that flows from point a to point b through the switch: is

For the circuit shown below, when the switch S is closed, then the total amount of charge that flows from point a to point b through the switch: is

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Grade:12

1 Answers

Arun
25763 Points
one year ago
When steady state is reached, the current I from the battery is 
9=I(3+6)orI=IA 
Potential difference across 3Ω resistance is 3 V and potential difference across
6Omega resistance is 6 V. 
Potential difference across 
3muF capacitor is 3V and pd 
across 6muF capacitor is 6 V. 
Therefore, charge on 3muF 
capacitor is 
Q_1 = 3 xx 3 = 9muC 

Charge on 6muF capacitor is 
Q_2 = 6 xx 6 = 36 muC 
Charge (-Q_1) is shifted from the positive plate of 6muF capacitor. 
The remaining charge on the positive plate of 6muF capacitor is 
shifted through the switch. Therefore, charge passing through 
the switch is

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