An exhausted zeolite bed was revived by 250 L of NaCl solution containing 50 g/L of NaCl solution. How many litres of hard water of hardness 250 ppm can be softened on the zeolite bed?

Question

Vikas TU · Answer

Dear student

V1 = Vol of Hard water
V2 = Vol of Nacl
solution containing xgL−1 used for the regeneration of the zeolite. Then hardness (H) is given by:
Hardness(H)=50*x*V2*10^3 / 58.3×V1
Ew of CaCO3 = 50
Mw of NaCl= 85.5
In the prioblem x=50gL−1, V2=250L, H=250p ,
We need to find V1
So, 250=50×50×250×10^3 / 58.5×V1
∴V1=42735L

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An exhausted zeolite bed was revived by 250 L of NaCl solution containing 50 g/L of NaCl solution. How many litres of hard water of hardness 250 ppm can be softened on the zeolite bed?

An exhausted zeolite bed was revived by 250 L of NaCl solution containing 50 g/L of NaCl solution. How many litres of hard water of hardness 250 ppm can be softened on the zeolite bed?

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An exhausted zeolite bed was revived by 250 L of NaCl solution containing 50 g/L of NaCl solution. How many litres of hard water of hardness 250 ppm can be softened on the zeolite bed?

An exhausted zeolite bed was revived by 250 L of NaCl solution containing 50 g/L of NaCl solution. How many litres of hard water of hardness 250 ppm can be softened on the zeolite bed?

1 Answers

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