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Grade: 11

                        

a rod rotates about point A .The rod is released from rest in the horizontal position so that it rotates about point A.[moment of inertia about point A =ml^2/3].find initial angular acceleration. [in the question how can we equate torque at A and torque due to mg.

a rod rotates about point A .The rod is released from rest in the horizontal position so that it rotates about point A.[moment of inertia about point A =ml^2/3].find initial angular acceleration. [in the question how can we equate torque at A and torque due to mg.

one year ago

Answers : (2)

Arun
25768 Points
							
Dear student
 
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10 months ago
Vikas TU
14149 Points
							
Dear student 
Question is not clear 
Please attach an image, 
We will happy to  help you 
Good Luck
Cheers
10 months ago
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