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A given light of wave length of 600 nm , wave length width is 0.2 nm . Find frequency width?
Answer- 1.67× 10^11
Please explain this in brief.

Draco , 7 Years ago
Grade 12th pass
anser 2 Answers
Susmita
\nu \lambda =c
\nu =\frac{c}{\lambda }
d\nu =\frac{-cd\lambda}{\lambda ^2}
         d\nu =\frac{-3*10^8*0.2*10^{-9}}{(600*10^{-9})^2}
            =1.67*10^{11}Hz
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Last Activity: 7 Years ago
Eshan
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Last Activity: 7 Years ago
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