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Grade: 12th pass 

                        
A given light of wave length of 600 nm , wave length width is 0.2 nm . Find frequency width? Answer- 1.67× 10^11 Please explain this in brief.
2 years ago

Answers : (2)

Susmita
425 Points 
							
\nu \lambda =c
\nu =\frac{c}{\lambda }
d\nu =\frac{-cd\lambda}{\lambda ^2}
         d\nu =\frac{-3*10^8*0.2*10^{-9}}{(600*10^{-9})^2}
            =1.67*10^{11}Hz
............................................................................................................................
2 years ago
Eshan
askIITians Faculty
2095 Points 
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2 years ago
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