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A and B are ideal gases the molecular weight of a and B are in the ratio of 1:4 the pressure of a gas mixture containing equal weights of A and B is P atm what is the partial pressure in atm of B in the mixture
Dear student Let Ma = aMb = b Xb = m/4a /(m/4a + m/a) = 1/5 Pb = Xb * P total = P/5 Hope it helps RegardsArun (askIITians forum expert)
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