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Grade: 12
        
50 Cal of heat is required to raise the temperature of 1 mole of an ideal gas from 20°C to 25°C, while the pressure of the gas is kept constant. The amount of heat required to raise the temperature of the same gas through same temperature range at constant volume is (R = 2 cal/mol/K)
 
  • 70 Cal
  • 60 Cal
  • 40 Cal
  • 50 cal
9 months ago

Answers : (1)

Arun
22578 Points
							
Given, cp = 50 cal  
According to the equation ,
cp=cv+nR(T2-T​1)
Thus, 50=cv+1 x 1.98 x 5 (value of R in cal K-1mol-1 is 1.98)
On solving we get c= 40.1 cal
9 months ago
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