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50 Cal of heat is required to raise the temperature of 1 mole of an ideal gas from 20°C to 25°C, while the pressure of the gas is kept constant. The amount of heat required to raise the temperature of the same gas through same temperature range at constant volume is (R = 2 cal/mol/K) 70 Cal 60 Cal 40 Cal 50 cal

50 Cal of heat is required to raise the temperature of 1 mole of an ideal gas from 20°C to 25°C, while the pressure of the gas is kept constant. The amount of heat required to raise the temperature of the same gas through same temperature range at constant volume is (R = 2 cal/mol/K)
 
  • 70 Cal
  • 60 Cal
  • 40 Cal
  • 50 cal

Grade:11

1 Answers

Arun
25763 Points
2 years ago
Given, cp = 50 cal  
According to the equation ,
cp=cv+nR(T2-T​1)
Thus, 50=cv+1 x 1.98 x 5 (value of R in cal K-1mol-1 is 1.98)
On solving we get c= 40.1 cal

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