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Grade 11AIPMT

The pH of buffer solution prepared by mixing 50 ml of 0.2 molar acetic acid and 25 ml of Sodium Acetate is 4.8 then the concentration of Sodium Acetate is pka Of Acetic Acid equals to 4.8

Profile image of Nayan
7 Years agoGrade 11
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1 Answer

Profile image of Arun
7 Years ago
Concentrations in the mixture: 

[CH3COOH] = 0.050*0.2/ 0.075 = 0.133 M 
[CH3COO-] = 0.025*x/0.075 = x/3 

pH = pKa + log[CH3COO-]/[CH3COOH] 

pKa = 4.76 
pH = 4.8 

0.04 = log[(x/3)/0.133] 
1.10 = x/0.40 
x = 0.44 

[CH3COO-] = x/3 = 0.15 M

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