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Sodium and chlorine react according to the following reaction: 2Na + Cl 2 → 2NaCl. If the reaction starts with 5.0 moles of Na and 3.0 moles of Cl 2 then which statement below is true? Cl 2 is the excess reagent and 5.0 moles of NaCl will be produced Na is the excess reagent and 2.5 moles of NaCl will be produced There will be an excess of 2.0 moles of Na Na is the limiting reagent and 2.0 moles NaCl will be produced Sodium and chlorine react according to the following reaction: 2Na + Cl2 → 2NaCl. If the reaction starts with 5.0 moles of Na and 3.0 moles of Cl2 then which statement below is true? Cl2 is the excess reagent and 5.0 moles of NaCl will be produced Na is the excess reagent and 2.5 moles of NaCl will be produced There will be an excess of 2.0 moles of Na Na is the limiting reagent and 2.0 moles NaCl will be produced
dear studentthe correct answer is(A)Na is the limiting reagent because the stoichiometric amount required in the reaction is 2 moles of Na with one mole of Cl2. But 3 moles of Cl2 are given with 5 moles of Na i.e. 1 mole of Cl2 per 5/3=1.66 mole of Na. But the stoichiometric amount required of Na is 2. Hence, Na is a limiting reagent. Hence, 2 moles of Na gives 2 moles of NaCl. So, 5 moles of Na will give 5 moles of NaCl.
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