if sinA+sinB=a, cosA+cosB=b prove that sin(A+B)=2ab/a^2+b^2

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Shailendra Kumar Sharma · Answer

SinA+SinB=a CosA+CosB=b Now a2+b2 = Sin 2 A+Cos 2 A+2SinACosA+Sin 2 B+Cos 2 B+2SinBCosB a 2 +b 2 -2=2(SinACosB+CosASinB) Sin(A+B)=(a 2 +b 2 -2)/2

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if sinA+sinB=a, cosA+cosB=b prove that sin(A+B)=2ab/a^2+b^2

if sinA+sinB=a, cosA+cosB=b prove that sin(A+B)=2ab/a^2+b^2

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if sinA+sinB=a, cosA+cosB=b prove that sin(A+B)=2ab/a^2+b^2

if sinA+sinB=a, cosA+cosB=b prove that sin(A+B)=2ab/a^2+b^2

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