Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A vernier caliper has 1 mm marks on the math scale. It has 20 equal divisions on the vernier scale (VSD) which match with 18 main scale divisions (MSD). For this vernier caliper, the least count (L.C.) is

A vernier caliper has 1 mm marks on the math scale. It has 20 equal divisions on the vernier scale (VSD) which match with 18 main scale divisions (MSD). For this vernier caliper, the least count (L.C.) is

Grade:Upto college level

1 Answers

Saurabh Singh
askIITians Faculty 49 Points
7 years ago
Least Count = Length of 1 MSD – Length of I VSD
Where MSD and VSD refer to Main Scale Division and Vernier Scale Division respectively
Generally N divisions on main scale coincide with N-1 divisions on vernier scale
1 VSD is equivalent to (N-1)/N main scale divisions
Using the formula for Least Count, we get
LC = 1 MSD – 1VSD
= 1 MSD – (N-1)/N MSD
= 1/N MSD


BUT

in this case
20 VSD=18MSD
so LC= length of 1 MSD - length of 1 VSD
LC=1mm-(18/20)*1mm
LC=0.1 mm

Thanks & Regards

Saurabh Singh,

askIITians Faculty

B.Tech.

IIT Kanpur

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free