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Grade: 12th pass
        a monochromatic light source of frequency f illuminate a metallic surface and eject a photo electron the photo electron having maximum energy are just able to ionize the hydrogen atom in ground state when the whole experiment is repeated with incident radiation of frequency 5/6f the photo electron are able to excite the hydrogen atom which then emits a radiation of wavelength 1215 angstrom find the frequency f
8 months ago

Answers : (1)

Eshan
askIITians Faculty
1805 Points
							Energy required ionize the hydrogen atom=13.6eV

hf=W_0+13.6eV

Since the atom in the second case de-excites to give out radiation of wavelength1215A^{\circ}, the energy of incident photoelectrons must also have been equal to the same energy=\dfrac{hc}{\lambda}=10.2eV
\implies \dfrac{5hf}{6}=W_0+10.2eV

Subtracting the two equations and solving gives,

f=4.92\times 10^{15}Hz
4 months ago
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