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A cation A^+4x and an anion B^-2x combine to form a compound. Similarly, C^+2x and D^-4x also combine to form a compound. When the molten compounds are subjected to electrolysis, the gaseous products obtained are in equimolar amounts. What should be the mole ratio of the compounds taken respectively?

A cation A^+4x and an anion B^-2x combine to form a compound. Similarly, C^+2x and D^-4x also combine to form a compound. When the molten compounds are subjected to electrolysis, the gaseous products obtained are in equimolar amounts. What should be the mole ratio of the compounds taken respectively?

Grade:11

2 Answers

Rishi Kumar
30 Points
one year ago
roud off or truncate to 2 digits
Iitian
19 Points
one year ago
The first compound formed by the combination of A^+4x and B^-2x is AB2.
The second compound formed by the combination of C^+2x and D^-4x is C2D.
On electrolysis of first compound, one molecule of Bgas evolves which have 2 atoms of B.
On electrolysis of the second compound, one atom of D evolves.
But, according to the question, the two gases evolved are equimolar,i.e., 2 atoms of D must evolve from the second compound.
Hence, the formula of the second compound can be better written as (C2D)2.
Clearly, the molar ratio of the two compounds taken=no. of molecules of AB2 in the first compound/no. of molecules of C2D in 2nf compound = 1:2.                                       Answer.
 

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