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        A block of mass M is connected to another block of mass M2 by a massless spring of force constant K the blocks are resting on a smooth horizontal plane the blocks are initially at rest and the spring and stretch then a constant force f is applied on block m to pull it find the force on the block M2
one year ago

Arun
24475 Points
							When 2 Blocks are in Contact -$F-f=m_{1}a$$f=m_{2}a$- wherein$a=\frac{F}{m_{1}+m_{2}}$$f=\frac{m_{2}F}{m_{1}+m_{2}}$Hope it helpsYou can ask as many queries on forum. We will be happy to help you.RegardsArun  $: Acceleration \: of\: the\: system\: a= \frac{F}{m+M}$$Force \: on \: block\: of \: mass\: m= ma= \frac{mF}{m+M}$

one year ago
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### Course Features

• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions