A ball released from the top of a towerof height h meters.It takes T seconds to reach the ground.What is the position of the ball in T/3 seconds?A. h/9 meters from ground. B.7h/9 meters from ground. C. 8h/9 meters from ground. D. 17h/18 meters from ground
ruchir , 10 Years ago
Grade
2 Answers
Saurabh Singh
Last Activity: 10 Years ago
distance travelled = (1/2)a*t^2
h=0.5*g*T^2
T=(2h/g)^0.5
now we need to fing distance travelled in T/3 seonds
= 0.5*g*(T/3)^2
=(0.5*g*T^2)/9
=(0.5*g*2*h/g)/9
=h/9
Thanks & Regards
Saurabh Singh,
askIITians Faculty
B.Tech.
IIT Kanpur
Himangshu
Last Activity: 10 Years ago
D T = (1/2)a*t^2
h=0.5*g*T^2
T=(2h/g)^0.5
now time=T/3 seonds
= 0.5*g*(T/3)^2
=(0.5*g*T^2)/9
=(0.5*g*2*h/g)/9
=h/9
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