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Three particles a b and c are thrown from the top of tower with same speed. A is thrown straight up b is thrown st. Down and c is thrown horizontally .they hit the ground with speeds va vb vc. which one is correct a)va = vc= vb b)vb>vc>va c)va= vb>vc d)va>vb=vc

Three particles a b and c are thrown from the top of tower with same speed. A is thrown straight up b is thrown st. Down and c is thrown horizontally .they hit the ground with speeds va vb vc. which one is correct
a)va = vc= vb
b)vb>vc>va
c)va= vb>vc
d)va>vb=vc

Grade:Upto college level

2 Answers

Althaf Hussain
37 Points
7 years ago

Answer (c).

 c)va= vb>vc 

When Particle A arrives back at the top of the tower, it will have the same downward speed as the upward speed it started with; its subsequent motion will be identical to that of Particle B. That va and vb are > vc is clear from the fact that A is freely "dropped" from its maximum height, which is greater than the height of the tower, hence greater than max height of C.

Vm
13 Points
3 years ago
Va=Vb=VcThe answer for the above question is option a they will have same velocities as they at last fall under the influence of gravity.

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