Badiuddin askIITians.ismu Expert
Last Activity: 14 Years ago
Dear manan
earlier i have replied to this problem ,at that time u have not maintion the complex root so i was only dealing real roots.
for complex root you have to solve it
(x-1)^3+8=0
(x-1)3+23=0
you can factorise it easly with the formula
a3 + b3 = (a+b)(a+bw)(a+bw2) where w is the cube root of unity
{(x-1)+2}{(x-1) +2w}{(x-1) +2w2} =0
( x+1)(x +2w-1)(x +2w2 -1) =0
it gives the root 1,1-2w,1-2w^2
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