Badiuddin askIITians.ismu Expert
Last Activity: 14 Years ago
DEar manan
nth root of unity is e0 ,e2π/n ,e4π/n ,e6π/n ,.......e2π(n-1)/n
now we have to find S = {e0}p +{e2π/n}p +{e4π/n}p +{e6π/n}p ,.......{e2π(n-1)/n}p
since p is multiple of n
so each term become e2πr form which is equal =1
so S =1+1+1...1
=n
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