Physical Chemistry> एक पिण्ड प्रथम 2 सैकेंड में 200मीटर की दू...

एक पिण्ड प्रथम 2 सैकेंड में 200मीटर की दूरी तय करती है अगले 4सैकेन्ड में 220मीटर की दूरी तय करती है तो प्रारम्भ से 7वें सैकेंड के अंत में पिण्ड का वेग करता होगा

Vikas , 4 Years ago

Grade 12th pass

2 Answers

Saurabh Koranglekar

Last Activity: 4 Years ago

Dear student

Using s = ut + 0.5 a t^2

Equation 1 is

200 = 2u + 0.5( a ) ( 4)

And equation 2 is

S6-s4 = ( u6-0.5a*36) - ( u2+ 0.5a*4)

Simplify and use these equations to obtain u and a and then find the required data

Regards

MAHIPAL VISHNOI

Last Activity: 2 Years ago

Make the equation according to question follow...

S =ut+1/2 at²

1. S=200m ,t=2s

Then 200=2u+1/2 a(4)

100 = u+a ...............(1)

2. S=(200+220)=420m,. t=(2+4)=6s

So 420=6u+1/2a(36)

70=u+3a................(2)

By equation 1&2

a= —15. u=115

Now, V=? For t=7

By V= U+at

V=115+(–15)7

V=10m/s

Solved By🎤📝 MAHIPAL VISHNOI

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Physical Chemistry> एक पिण्ड प्रथम 2 सैकेंड में 200मीटर की दू...

Vikas , 4 Years ago

Saurabh Koranglekar

MAHIPAL VISHNOI

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