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You are designing an elevator for a hospital. The force exerted on a passenger by the floor of the elevator is not to exceed 1.60 times the passenger's weight. The elevator accelerates upwards with constant acceleration for a distance of 3.0m and then starts to slow down. What is the maximum speed (inms−1) of the elevator?

Harshit Singh , 4 Years ago
Grade 12th pass
anser 1 Answers
Yash Patari
DEAR STUDENT

Form the  FBD of the passenger

Nmg=ma
N=(1.6)mg
we get a=0.6g
Intial velocity of elevator is zero,
using equation of motion, v2=u2+2as
v2=2(0.6g)×3
we get v=6m/s
THANKS
Last Activity: 4 Years ago
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