Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
Let the retarding force be F.
Suppose A having mass ‘m’ was initially moving with velocity ‘u’. It comes to rest in time ‘t’ after traveling a distance ‘x’.
Retardation of this mass is, a = F/m
And B having mass ‘M’ was initially moving with velocity ‘U’. It comes to rest in time ‘T’ after traveling a distance ‘X’.
Retardation of this mass is, A = F/M
A/Q,
t = 2T
x = X/3
Also,
F = ma = MA
For A,
0 = u – at
=> a = u/t
Similarly,
A = U/T
So,
a/A = uT/(Ut)
=> a/A = uT/(U × 2T)
=> a/A = u/(2U) ……………….(1)
Again for A,
02 = u2 – 2ax
=> a = u2/(2x)
A = U2/(2X)
a/A = [u2/(2x)]/[U2/(2X)]
=> a/A = (u2/U2)(X/x)
=> a/A = (u2/U2)[X/(X/3)]
=> a/A = 3(u2/U2) ………………(2)
(1) and (2) => u/(2U) = 3(u2/U2)
=> ½ = 3 u/U
=> u/U = 1/6
Thus, ratio of initial velocity of A to initial velocity of B is = 1 : 6
Regards
Arun (askIITians forum expert)
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !