The height of the body after 5 s from the ground is (g=9.8m/s2).

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Pawan Prajapati · Answer

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Yash Patari · Answer

DEAR STUDENT The height of the body after 5 s from the ground is (g=9.8m/s2)? ANSWER v = u + g t t = 5 s e c u = 0 ∣ v ∣ = 5 g = 5 × 9 . 8 = 4 9 m / s THANKS TEAM ASKIITIANS

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The height of the body after 5 s from the ground is (g=9.8m/s2).

The height of the body after 5 s from the ground is (g=9.8m/s2).

2 Answers

v=u+gt
t=5 sec
u=0
∣v∣=5g=5×9.8=49 m/s

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The height of the body after 5 s from the ground is (g=9.8m/s2).

The height of the body after 5 s from the ground is (g=9.8m/s2).

2 Answers

v=u+gtt=5 secu=0∣v∣=5g=5×9.8=49 m/s

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v=u+gt
t=5 sec
u=0
∣v∣=5g=5×9.8=49 m/s