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let initial velocity = u & accleration is a then
distance travelled in 5 sec = S7
using , s=ut + at2/2
S7 = 5u + a49/2
= (10u+49a) / 2
distance covered in 2 sec = S2 = 2u + 4a/2
=2u+2a = 200 (given)
u+a = 100 .....1
now distance covered in 2 to 7 sec is given 220cm
S7-200 = 220
(10u+49a) / 2 = 420
10 u+ 49 a = 840 ........2
from 1& 2
find a and u then you will be able to solve velocity after 7th second
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