Send 3 a body travel 220 in 1st to 2nd and the 220 CM in at 5:13 calculate the velocity at the end of 7 seconds from the start please solve questions of motion class 9

let initial velocity = u & accleration is a then

distance travelled in 5 sec = S₇

using , s=ut + at²/2

S₇ = 5u + a49/2

=  (10u+49a) / 2

distance covered in 2 sec = S₂ = 2u + 4a/2

=2u+2a = 200 (given)

u+a = 100    .....1

now distance covered in 2 to 7 sec is given 220cm

S₇-200 = 220

(10u+49a) / 2 = 420       

10 u+ 49 a = 840    ........2

from 1& 2

find a and u then you will be able to solve velocity after 7^th second