Calculate the position of the planet of 10^5 kg which is placed between the planets of 10^20kg and 10^24 kg which are placed at 6000km apart hence it will get zero gravitational force

Question

Vikas TU · Answer

Hiii The gravitation force acting between two bodies is given by F = G M1M2/d 2 So, Let us assume the distance between 10^20 kg and 10^5 kg mass be d then distance between 10^24 Kg and 10^5 Kg mass wil be equal to 6000-d, Apply Gravitational force formula on Both you will get the value of d .

Thank you for registering.

Register Now and Win Upto 25% Scholorship for a Full Academic Year !

Enter Your Details

Registration done!

Guest

Calculate the position of the planet of 10^5 kg which is placed between the planets of 10^20kg and 10^24 kg which are placed at 6000km apart hence it will get zero gravitational force

Calculate the position of the planet of 10^5 kg which is placed between the planets of 10^20kg and 10^24 kg which are placed at 6000km apart hence it will get zero gravitational force

1 Answers

Think You Can Provide A Better Answer ?

Other Related Questions on 9 grade science

ASK QUESTION

Answer and earn gift vouchers

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Complete Self Study Package designed by Industry Leading Experts

Live 1-1 coding classes to unleash the Creator in your Child

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Register Now & Win Upto 25% Scholorship

Thank you for registering.

Register Now and Win Upto 25% Scholorship for a Full Academic Year !

Enter Your Details

Registration done!

Guest

IIT JEE Courses

One Year IIT Programme

Two Year IIT Programme

Crash Course

NEET Courses

One Year NEET Programme

Two Year NEET Programme

One to One

School Board

Live Online classes

Class 11 & 12

Class 9 & 10

Class 6, 7 & 8

Test Series

JEE test series

NEET test series

C.B.S.E test series

Complete Self Study Packages

FULL COURSE

For class 12th

For class 11th

Calculate the position of the planet of 10^5 kg which is placed between the planets of 10^20kg and 10^24 kg which are placed at 6000km apart hence it will get zero gravitational force

Calculate the position of the planet of 10^5 kg which is placed between the planets of 10^20kg and 10^24 kg which are placed at 6000km apart hence it will get zero gravitational force

1 Answers

Think You Can Provide A Better Answer ?

Other Related Questions on 9 grade science

ASK QUESTION

Answer and earn gift vouchers

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Complete Self Study Package designed by Industry Leading Experts

Live 1-1 coding classes to unleash the Creator in your Child

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Register Now & Win Upto 25% Scholorship