An object starts moving from rest on a straight line path with uniform acceleration and covers a distance of 100 m in first 10 s. The distance it covers in next 5 s ?

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Amarjit · Answer

Let`s first calculate the acceleration using the formula s=ut+1/2at².Acceleration comes up to be 2m/sec².Now again using the formula s=ut+1/2 at² we calculate the total distance travelled in 15 seconds.The total distance travelled comes up to be 225m.Hence finally the distance travelled in the next 5seconds will be 125 m.

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An object starts moving from rest on a straight line path with uniform acceleration and covers a distance of 100 m in first 10 s. The distance it covers in next 5 s ?

An object starts moving from rest on a straight line path with uniform acceleration and covers a distance of 100 m in first 10 s. The distance it covers in next 5 s ?

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An object starts moving from rest on a straight line path with uniform acceleration and covers a distance of 100 m in first 10 s. The distance it covers in next 5 s ?

An object starts moving from rest on a straight line path with uniform acceleration and covers a distance of 100 m in first 10 s. The distance it covers in next 5 s ?

1 Answers

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