Join now for JEE/NEET and also prepare for Boards Join now for JEE/NEET and also prepare for Boards. Register Now
Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
An object starts moving from rest on a straight line path with uniform acceleration and covers a distance of 100 m in first 10 s. The distance it covers in next 5 s ? An object starts moving from rest on a straight line path with uniform acceleration and covers a distance of 100 m in first 10 s. The distance it covers in next 5 s ?
Let`s first calculate the acceleration using the formula s=ut+1/2at².Acceleration comes up to be 2m/sec².Now again using the formula s=ut+1/2 at² we calculate the total distance travelled in 15 seconds.The total distance travelled comes up to be 225m.Hence finally the distance travelled in the next 5seconds will be 125 m.
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -