An arrow shaft when shot vertically losses it's 60% energy in 3 seconds. The maximum height that can be reached by arrows is?

Question

Arun · Answer

Let the initial speed be u ,, so after 3 sec it speed will be 2/5u

so from first equation of motion
v = u + at

2/5u = u - 9.8×3

u = 9.8×3×5/3 = 49m/s
u = 49m/s

Now third equation of motion

v^2=u^2+2as

at maximum height , V = 0

, So H = u^2/2g

H = 49×49/2×9.8

H = 122.5 m

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An arrow shaft when shot vertically losses it's 60% energy in 3 seconds. The maximum height that can be reached by arrows is?

An arrow shaft when shot vertically losses it's 60% energy in 3 seconds. The maximum height that can be reached by arrows is?

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An arrow shaft when shot vertically losses it's 60% energy in 3 seconds. The maximum height that can be reached by arrows is?

An arrow shaft when shot vertically losses it's 60% energy in 3 seconds. The maximum height that can be reached by arrows is?

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