Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
An arrow shaft when shot vertically losses it's 60% energy in 3 seconds. The maximum height that can be reached by arrows is?
Let the initial speed be u ,, so after 3 sec it speed will be 2/5uso from first equation of motion v = u + at 2/5u = u - 9.8×3u = 9.8×3×5/3 = 49m/su = 49m/sNow third equation of motion v^2=u^2+2as at maximum height , V = 0 , So H = u^2/2g H = 49×49/2×9.8 H = 122.5 m
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -