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A stone is thrown vertically upwards with an initial velocity of v what is the distance covered in time 1.5v/g

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2 years ago

## Answers : (1)

Arun
24742 Points
```							Dear Akshat P = v - g * t(1)t(1)= v/g 0² = v² - 2g HH = v²/2gSo during time t(1), stone will travel = v²/2g = 0.5 v²/g Remaining time(t2) = (1.5 -1) v /g = 0.5 v/g Durung next phase of its downward journey, it starts with velocity =0, and after time( t2 = 0.5 v/g)Its displacement wil be =h = 0 *t(2) + (1/2) g* t²h = (1/2) g* (0.5 v/g)²h = 0.125 v²/g Hence totak distance covered = (0.5 +0.125) v²/g= 0.625 v²/g RegardsArun (askIITians forum expert)
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2 years ago
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• Test paper with Video Solution
• Mind Map
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