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A stone is thrown vertically upward with an initial velocity u from the top of a tower. It reaches the ground with a velocity 3u. The height of the Tower is? Explain

A stone is thrown vertically upward with an initial velocity u from the top of a tower. It reaches the ground with a velocity 3u. The height of the Tower is? Explain

Grade:9

2 Answers

Shivangi Khatter
askIITians Faculty 468 Points
3 years ago
575-1448_2.PNG
john cena
35 Points
3 years ago
intial velocity= u
displacement=height of tower=s
So, final velocity= 3u
acceleration= g
from third equation of motion:-
v- u = 2as
9u2 – u = 2 * g * s
8u2 = 2 * 9.8 * s
s = 0.42 * u2
s = 0.42u2
hence the height of tower is “0.42u2

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