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A stone is thrown vertically upward with an initial velocity u from the top of a tower. It reaches the ground with a velocity 3u. The height of the Tower is? Explain
intial velocity= udisplacement=height of tower=sSo, final velocity= 3uacceleration= gfrom third equation of motion:-v2 - u2 = 2as9u2 – u2 = 2 * g * s8u2 = 2 * 9.8 * ss = 0.42 * u2s = 0.42u2hence the height of tower is “0.42u2”
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