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Grade: 9 

                        
A stone is thrown vertically upward with an initial velocity u from the top of a tower. It reaches the ground with a velocity 3u. The height of the Tower is? Explain
2 years ago

Answers : (2)

Shivangi Khatter
askIITians Faculty
468 Points 
							575-1448_2.PNG
2 years ago
john cena
35 Points 
							
intial velocity= u
displacement=height of tower=s
So, final velocity= 3u
acceleration= g
from third equation of motion:-
v2 - u2  = 2as
9u2 – u2  = 2 * g * s
8u2 = 2 * 9.8 * s
s = 0.42 * u2
s = 0.42u2
hence the height of tower is “0.42u2”
2 years ago
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