A stone is thrown vertically upward with an initial velocity u from the top of a tower. It reaches the ground with a velocity 3u. The height of the Tower is? Explain

Question

Shivangi Khatter · Answer

john cena · Answer

intial velocity= u displacement=height of tower=s So, final velocity= 3u acceleration= g from third equation of motion:- v 2 - u 2 = 2as 9u 2 – u 2 = 2 * g * s 8u 2 = 2 * 9.8 * s s = 0.42 * u 2 s = 0.42u 2 hence the height of tower is “0.42u 2 ”

Thank you for registering.

Register Now and Win Upto 25% Scholorship for a Full Academic Year !

Enter Your Details

Registration done!

A stone is thrown vertically upward with an initial velocity u from the top of a tower. It reaches the ground with a velocity 3u. The height of the Tower is? Explain

A stone is thrown vertically upward with an initial velocity u from the top of a tower. It reaches the ground with a velocity 3u. The height of the Tower is? Explain

2 Answers

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

Other Related Questions on 9 grade science

ASK QUESTION

Answer and earn gift vouchers

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Complete Self Study Package designed by Industry Leading Experts

Live 1-1 coding classes to unleash the Creator in your Child

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Register Now & Win Upto 25% Scholorship