A stone is thrown vertically upward with an initial velocity u from the top of a tower. It reaches the ground with a velocity 3u. The height of the Tower is? Explain

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Shivangi Khatter · Answer

john cena · Answer

intial velocity= u displacement=height of tower=s So, final velocity= 3u acceleration= g from third equation of motion:- v 2 - u 2 = 2as 9u 2 – u 2 = 2 * g * s 8u 2 = 2 * 9.8 * s s = 0.42 * u 2 s = 0.42u 2 hence the height of tower is “0.42u 2 ”

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A stone is thrown vertically upward with an initial velocity u from the top of a tower. It reaches the ground with a velocity 3u. The height of the Tower is? Explain

A stone is thrown vertically upward with an initial velocity u from the top of a tower. It reaches the ground with a velocity 3u. The height of the Tower is? Explain

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A stone is thrown vertically upward with an initial velocity u from the top of a tower. It reaches the ground with a velocity 3u. The height of the Tower is? Explain

A stone is thrown vertically upward with an initial velocity u from the top of a tower. It reaches the ground with a velocity 3u. The height of the Tower is? Explain

2 Answers

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