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A particle is projected horizontally from the top of the cliff of height ‘H’ with a velocity of √(2gH). The radius of curvature of the trajectory at the instant of projection will be?

Parijat , 6 Years ago
Grade 9
anser 1 Answers
Eshan

Last Activity: 6 Years ago

Speed of projection=\sqrt{2gH}

The acceleration of the body at this moment=g

Assuming the motion to be circular momentartily, the acceleration of the body would be given as

g=\dfrac{v^2}{R}
\implies R=\dfrac{v^2}{g}=2H

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