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A parachutist after bailing out falls 50 m without friction.When the parachute opens,it decelerates at 2ms-2.He reches the ground with the speed of 3ms-1.At what height did he bail out?

Ansh Patel , 10 Years ago
Grade 10
anser 1 Answers
pranav taysheti

Last Activity: 10 Years ago

Here, In this question.

Initial velocity = 50m/s
Acceleration = 2m/s2
final velocity = 3m/s

So therefore,

v2 = u2 + 2as

we get by that,

623.25m

sorry i could not include whole answer here.
 

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