A hammer of Mass 500gm moving at 50 m per second Strike a nail. The nail stops hammer in 0.01sec what is a force of the nail on the hammer

• Here, m = 500 g = 0.5 kg, u = 50 ms–1, u = 0, t = 0.01 s
• The force of nail on the hammer,

1.  F =  Change in momentum                                                                                                                                                                 time
2.  F = m(v - u) /  t

                 = 0.5 (0 - 50)

                        0.01

                 =   –2500 N

• The negative sign means that the force of nail on the hammer is acting in the direction opposite to that of hammer.

Regards

Arun(askIITians forum expert)