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`        	A compound on analysis gave the following percentage composition C = 54.54%, H, 9.09%, O = 36.36 %. The vapour density of the compound was found to be 44. Find out the molecular formula of the compound.I am preparing for ftre so that i need`
4 years ago

```																Element									Percentage									Relative number of moles									Simple ratio moles									Simplest whole number ratio													C									54.54									  54.54			------- -  =  4.53			    12									  4.53			--------  = 2 			  2.27									2													H									9.09									   9.09			--------    =  9.09			     1									  9.09			--------  = 4			  2.27									4													O									36.36									  36.36			----------  =  2.27			    16									  2.27			---------  =  1			  2.27									1						 Calculation of Molecular formulaEmpirical formula mass = 12 x 2 + 1 x 4 + 16 x 1 = 44Molecular mass =  2 x   Vapour density = 2 x 44 = 88             Molecular mass                       88n = ------------------------------------  = ---------   = 2        Empirical Formula mass              44 = C2H4O        x   2= C4H8O2									Element									Percentage									Relative number of moles									Simple ratio moles									Simplest whole number ratio													C									54.54									  54.54			------- -  =  4.53			    12									  4.53			--------  = 2 			  2.27									2													H									9.09									   9.09			--------    =  9.09			     1									  9.09			--------  = 4			  2.27									4													O									36.36									  36.36			----------  =  2.27			    16									  2.27			---------  =  1			  2.27									1						 Calculation of Molecular formulaEmpirical formula mass = 12 x 2 + 1 x 4 + 16 x 1 = 44Molecular mass =  2 x   Vapour density = 2 x 44 = 88             Molecular mass                       88n = ------------------------------------  = ---------   = 2        Empirical Formula mass              44 = C2H4O        x   2= C4H8O2
```
4 years ago
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