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# a body travels 2 m in 2nd second & 6 m in next 4 seconds. what will be the distance travelled in 9th second?

Aarti Gupta
5 years ago
For nth second the distance travelled is given as--
S = u + a/2 (2n + 1)
where,
S = distance travelled
u = initial velocity
a = acceleration
For 2nd second,
2 = u + a/2 (2* 2 + 1) ------ (as distance travelled in 2nd sec is 2m)
2u + 5a = 4 -------- (1)
Now for distance travelled in 4th second,
S = ut + ½ at2
6 = 4u + ½ a (4)2 --------- (distance travelled in 4sec is 6m)
2u + 4a = 3 --------(2)
On solving (1) and (2) we get,
a = 1m/s2 and putting this value in any equation we get, u = – 0.2m/s( negative sign indicates the opposite direction)
thus for 9th second,
S = u + a/2 (2n+1)
S = -0.5 + 1/2(2*9 + 1)
S = 9m