Falling Behind in Studies? Join Our Performance Improvement Batch. Enroll For Free
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
A body os projected up with inital velocity u m/s . it goes up to height h meter in time t second.Then it comes back at projection point .consider negligible air resistance,which is true? 1.acceleration is 0. 2.displacement is 0. 3.average velocity is 2h/t. 4.final velocity is 2u at projection point
answer is 2. displacement is 0 as it reaches the point it was projected fromwhy other options are wrong:1.accerelation under freefall is always g which is equal to 9.8 meters per second square.3.average speed is 2h/t but as velocity is a vector quantity , velocity will be 0.4.final velocity at projection point would be root over 2gh – u(square). thiss can be obtained by reaaranging v(square)-u(square)=2gh
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -