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a body moves with a uniform acceleration and travels 270metre in 3second. find the velocity of the body at 10second after the start.
t= 3s......s=270m. => applying newtons second equation of motion, =>s=ut + ½at²=> u=0=> s=½at²=> 270=½a (3)²=> a= 60 m/s²=> now apply bewtons first eqn. of motion,=> v=u +at=> v =0+ 60*10=> v=600 m/s .......(Ans)
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