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a block of mass 2 kg is lying on the frictionless table .Aforce of 8N is applied on it for 12 s.Calculate its kinetic energy.

Asiya Hassan , 10 Years ago
Grade 9
anser 1 Answers
Vikas TU

Last Activity: 10 Years ago

From first law of eqn.
v = u + at
v = 0 + 8/2 x 12 = 48 m/s
 
  1. E = 0.5 x 2 x 48 x 48 J
  2. Now U can calculate..
Plz  approve!!!
 
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