A baloon is at a height of 81m and is ascending upward with a velocity of 12 m/s. A body of 2kg weight is dropped from it. If g =10m/s^2,then body will reach the surface of the earth in how many time?

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Vikas TU · Answer

h = h0 + vt – 0.5gt^2 Surface will hit when h =0 h0 + vt – 0.5gt^2 = 0 thus, 81 + 12t – 5t^2 = 0Solutions are t= -2 and t = 5.4 s thus discarding -3

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A baloon is at a height of 81m and is ascending upward with a velocity of 12 m/s. A body of 2kg weight is dropped from it. If g =10m/s^2,then body will reach the surface of the earth in how many time?

A baloon is at a height of 81m and is ascending upward with a velocity of 12 m/s. A body of 2kg weight is dropped from it. If g =10m/s^2,then body will reach the surface of the earth in how many time?

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A baloon is at a height of 81m and is ascending upward with a velocity of 12 m/s. A body of 2kg weight is dropped from it. If g =10m/s^2,then body will reach the surface of the earth in how many time?

A baloon is at a height of 81m and is ascending upward with a velocity of 12 m/s. A body of 2kg weight is dropped from it. If g =10m/s^2,then body will reach the surface of the earth in how many time?

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