A ball is thrown vertically upwards with a velocity of 10 m/s.It returns to the ground with a velocity of 9 m/s.What is the height attained by the ball ?

Question

SURESH · Answer

dear vijaya patel, we know the equation of height h=u^2/2g (g=gravity of earth is 9.8 m/s^2) & u is initial velocity i.e.,10 m/s we caliculate by this formula we get 5.102 m so, the ball reached 5.102 m.

Vijeya Patel · Answer

But in both the cases the distance is different sir.(when going up and coming down).What about that?and my textbook gives th answer 4.62m ,but I don’t understand how?please help

NARAYANA · Answer

WE KNOW THE EQUATION FOR HIGHT ANY OBJECT THROWN WITH INTIAL VELOCITY(U),GRAVITY(g)THEN EQUATION IS U^2/2g,SO ANSWER IS 10^2/2*9.8=5.10M

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A ball is thrown vertically upwards with a velocity of 10 m/s.It returns to the ground with a velocity of 9 m/s.What is the height attained by the ball ?

A ball is thrown vertically upwards with a velocity of 10 m/s.It returns to the ground with a velocity of 9 m/s.What is the height attained by the ball ?

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