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Grade: 9

                        

A ball dropped from a height covers half of its journey from top of a tower in 0.5 seconds the height of the Tower is :(take g =9.8)? Explain

2 years ago

Answers : (2)

Shivangi Khatter
askIITians Faculty
468 Points
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2 years ago
john cena
35 Points
							
initially the ball at rest so initial speed= o
height of tower= h
acceleration= g= 9.8 m/s2
so from second equation of motion:-
s= ut + ½ at2
s= ½  * g * (0.5)2
s= ½ * 9.8 * 0.25
s= 4.98 * 0.25
s= 1.225m
hence 1.225m is the half journey and half height of tower
so twice of 1.225m is the full height of tower
so, 1.225 * 2= 2.45m
hence height of tower is 2.45m
2 years ago
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