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A ball dropped from a height covers half of its journey from top of a tower in 0.5 seconds the height of the Tower is :(take g =9.8)? Explain

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2 years ago

Shivangi Khatter
468 Points
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2 years ago
john cena
35 Points
```							initially the ball at rest so initial speed= oheight of tower= hacceleration= g= 9.8 m/s2so from second equation of motion:-s= ut + ½ at2s= ½  * g * (0.5)2s= ½ * 9.8 * 0.25s= 4.98 * 0.25s= 1.225mhence 1.225m is the half journey and half height of towerso twice of 1.225m is the full height of towerso, 1.225 * 2= 2.45mhence height of tower is 2.45m
```
2 years ago
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