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a ball dropped foma first floor of a building reaches the ground in 0.9 seconds.taking g=10m/s2 what is the average speed of the ball during 0.9s? a ball dropped foma first floor of a building reaches the ground in 0.9 seconds.taking g=10m/s2 what is the average speed of the ball during 0.9s?
Since we know that:V=u+atAnd it is given in the question that the body is dropped, soU=0Now we know here a=10m/s and t=0.9secV=10×0.9=9m/s
u=0t=0.9 seca=10 m/s^2Therefore, using the second equation of motion,s=ut+1/2a(t)^2s=1/2*10*(0.9)^2s=5*0.81s=4.05mNow, we know that average speed= Total distance/Total time = 4.05/0.9 = 4.5 m/s
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