Write four solutions for each of the following equations:

(i) 2x + y = 7

Dear Student

To find the four solutions of 2x + y = 7 we substitute different values for x and y

x = 0

Then,

2x + y = 7

(2×0)+y = 7

y = 7

(0,7)

Let x = 1

Then,

2x + y = 7

(2×1)+y = 7

2+y = 7

y = 7 – 2

y = 5

(1,5)

Let y = 1

Then,

2x + y = 7

2x+ 1 = 7

2x = 7 – 1

2x = 6

x = 3

(3,1)

Let x = 2

Then,

2x + y = 7

2(2)+y = 7

4+y = 7

y = 7 – 4

y = 3

(2,3)

Thus, The solutions are (0, 7), (1,5), (3,1), (2,3)

Thanks