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The value of (logm+logm2+logm3+....+logmn) is equal to (a)n(n+1)2 (b)mn2 (c)n(n+1)2logm (d)n(n+1).logm2

The value of (logm+logm2+logm3+....+logmn)
is equal to
(a)n(n+1)2

(b)mn2

(c)n(n+1)2logm

(d)n(n+1).logm2

Grade:12th pass

1 Answers

Pawan Prajapati
askIITians Faculty 60787 Points
2 years ago
Our expert is working on this Class IX Maths answer. We will update the answer very soon.

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