The sum of three consecutive odd numbers is more than 207, how do you find the minimum values of these integers?

To find the minimum values of three consecutive odd numbers whose sum is more than 207, you can set up an equation and solve for the smallest possible values.

Let's represent the three consecutive odd numbers as follows:

1st odd number = x
2nd odd number = x + 2 (since consecutive odd numbers have a difference of 2)
3rd odd number = x + 4

Now, you want the sum of these three numbers to be more than 207:

x + (x + 2) + (x + 4) > 207

Now, solve for x:

3x + 6 > 207

Subtract 6 from both sides:

3x > 201

Now, divide both sides by 3:

x > 67

So, the smallest possible value for the first odd number (x) that satisfies the condition is 67. The second odd number would be 67 + 2 = 69, and the third odd number would be 67 + 4 = 71.

Therefore, the minimum values of the three consecutive odd numbers are 67, 69, and 71, and their sum is 67 + 69 + 71 = 207, which is just barely more than 207.