In figure PQRS and ABRS are parallelograms and X is any point on side BR. Show that ar(PQRSJ = ar(ABRS) (i) (ii) ar(AXS) = jar(PQRS).

. (i) As parallelograms PQRS and ABRS are on the same base SR and between the same parallels SR and PB. Hence, ar(PQRS) = ar(ABRS). (ii) Triangle XAS end parallelo­ gram ABRS are on the same base AS and between the same parallels AS and BR. s R ar(AXS) = !.ar