In figure PQRS and ABRS are
parallelograms and X is any point on side BR. Show that
ar(PQRSJ = ar(ABRS)
(i)
(ii) ar(AXS) = jar(PQRS).

Question

In figure PQRS and ABRS are parallelograms and X is any point on side BR. Show that ar(PQRSJ = ar(ABRS) (i) (ii) ar(AXS) = jar(PQRS).

Pawan Prajapati · Answer

. (i) As parallelograms PQRS and ABRS are on the same base SR and between the same parallels SR and PB. Hence, ar(PQRS) = ar(ABRS). (ii) Triangle XAS end parallelo­ gram ABRS are on the same base AS and between the same parallels AS and BR. s R ar(AXS) = !.ar<ABRS) 2 But ar(ABRS) = a.r(PQRS) [From result of part (i)] .. ar(AXS) = 2ar(PQRS).

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In figure PQRS and ABRS are parallelograms and X is any point on side BR. Show that ar(PQRSJ = ar(ABRS) (i) (ii) ar(AXS) = jar(PQRS).

In figure PQRS and ABRS are
parallelograms and X is any point on side BR. Show that
ar(PQRSJ = ar(ABRS)
(i)
(ii) ar(AXS) = jar(PQRS).

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