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In figure, ABCDE is a pentagon. A line through B paralkl to AC meets E DC produced at F. Show that (i") ar(ACBJ = ar(ACFJ (ii) ar(AEDFJ = ar(ABCDEJ

In figure, ABCDE is a pentagon. A line through B paralkl to AC meets E DC produced at F. Show that
(i") ar(ACBJ = ar(ACFJ
(ii) ar(AEDFJ = ar(ABCDEJ

Grade:12th pass

1 Answers

Pawan Prajapati
askIITians Faculty 60787 Points
3 years ago
Triangles ABC and AFC are on the same base AC and between the same parallels AC and BF. (i) :. cu(ACB) = ar(ACF). (ii) Adding ar(AEDC) to both sides, we t cu(ACB) + cu(AEDC) = cu(ACF) + cu(AEDC) cu(ABCDE) = ar(AFCDE) or ar(ABCDE) = ar(AEDF)

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